{VERSION 5 0 "IBM INTEL NT" "5.0" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 1 255 0 0 1 0 1 0 0 1 0 0 0 0 1 }{PSTYLE "Normal" -1 0 1 {CSTYLE "" -1 -1 "Times" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }1 1 0 0 0 0 1 0 1 0 2 2 0 1 }} {SECT 0 {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 152 "#\n# Randomisierter zweistufiger Pr\374fplan:\n# Bestimmung der Randomisierungsgewichte d elta1,delta2,delta3 so,\n# dass L(p_alpha)=alpha und L(p_beta)=beta\n# " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "restart;" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 40 "# hyp(k) = Pr\{X1 = k\} = P\{H(N,M, n1) = k\}" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 63 "hyp := k ->1.0*binomia l(M,k)*binomial(N-M,n1-k)/binomial(N,n1);" }}}{EXCHG {PARA 0 "> " 0 " " {MPLTEXT 1 0 50 "# hyp2(j,k) = Pr\{X2|j = k\} = P\{H(N-n1,M-j,n2) = \+ k\}" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 79 "hyp2 := (j,k) -> 1.0*binomia l(M-j,k)*binomial(N-n1-M+j,n2-k)/binomial(N-n1,n2);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "N:=5000;" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "n1:=100;" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 " n2:=200;" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 6 "c1:=0;" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 6 "d1:=3;" }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 5 "c:=6;" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 27 "# Berechnung von L(p_alpha)" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 23 "M:=50; # p_alpha = 0.01" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 92 "# Annahmewahrscheinlichkeit bei 1. Stichprobe\nL_alph a := sum(hyp(i),i=0..c1)-delta1*hyp(c1);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 113 "# Annahmewahrscheinlichkeit bei 2. Stichprobe\n# sum (P\{X1 = j\}*(P\{X2|j <= c-j\}-delta3*P\{X2|j = c-j\}, j=c1+1..d1-1)" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 5 "A:=0;" }}}{EXCHG {PARA 0 " > " 0 "" {MPLTEXT 1 0 5 "B:=0;" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 100 "for j from c1+1 to d1-1 do\n A:=A+hyp(j)*sum(hyp2(j,i),i=0.. c-j);\n B:=B+hyp(j)*hyp2(j,c-j);\nend do:" }}}{EXCHG {PARA 0 "> " 0 " " {MPLTEXT 1 0 28 "L_alpha:=L_alpha+A-delta3*B;" }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 18 "# Randpunkte c1,d1" }}}{EXCHG {PARA 0 "> " 0 " " {MPLTEXT 1 0 362 "if (c1 " 0 "" {MPLTEXT 1 0 23 "L_alpha := simplify(%);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 2 "# " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 26 "# Ber echnung von L(p_beta)" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 26 "M \+ := 150; # p_beta = 0.03" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 45 "L_beta := sum(hyp(i),i=0..c1)-delta1*hyp(c1);" }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 5 "A:=0;" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 5 "B:=0;" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 100 "for j from c 1+1 to d1-1 do\n A:=A+hyp(j)*sum(hyp2(j,i),i=0..c-j);\n B:=B+hyp(j)* hyp2(j,c-j);\nend do:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 26 "L_ beta:=L_beta+A-delta3*B;" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 322 "if (c1 " 0 "" {MPLTEXT 1 0 22 "L_beta := simplify( %);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 10 "delta1:=1;" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 28 "unassign('delta2','delta3'); " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 49 "fsolve(\{L_alpha-0.9,L_ beta-0.1\},\{delta2,delta3\});" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 10 "assign(%);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 30 "#\n# \+ Maximum der ASN-Funktion\n#" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 18 "unassign('M','j');" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 44 "# hyper(M,k) = Pr\{X1 = k\} = P\{H(N,M,n1) = k\}" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 69 "hyper := (M,k) ->1.0*binomial(M,k)*binomial(N-M,n1-k) /binomial(N,n1);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 222 "# ASN- Funktion als Funktion von M\nif (c1 n1 + n2*( sum(hyper(M,j),j=c1+1..d1-1)+delta1*hyper(M,c1)+delta2*hyper(M,d1));\n elif (c1=d1) then\n ASN := M -> n1 + n2*(delta1+delta2-1)*hyper(M,c1) ;\nend if ;" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 91 "print ('M',' p','ASN(p)');\nfor M from 0 by 10 to 100 do\n print(M,evalf(M/N),ASN( M))\nend do;" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}{MARK "34 0 0" 10 }{VIEWOPTS 1 1 0 1 1 1803 1 1 1 1 }{PAGENUMBERS 0 1 2 33 1 1 }